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Nov 8, 2012 · PDF Focus.Net - How to convert PDF to Word using C#. SautinSoft.Duration: 4:17 Posted: Nov 8, 2012

i i i where N1 and N2 are unknown integers and Ir is the residual ionospheric error between the rover and base To successfully implement a range space DGPS system, the base station must, at a minimum, broadcast the following set of information for each satellite: satellite id, range and phase corrections, ephemeris set identi er, and a reference time A roving receiver then selects the most appropriate set of satellites for its circumstances The ephemeris set identi er is crucial because the satellite clock and position errors are distinct for each ephemeris set When a new ephemeris set becomes available, for practical reasons, it is also standard practice to send corrections for both the new and old ephemeris set for some short period of time to allow rovers to download the new ephemeris set

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Nov 8, 2012 · PDF Focus.Net - How to convert PDF to Word using C#. SautinSoft.Duration: 4:17 Posted: Nov 8, 2012

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method of finding phase angle in a circuit containing resistance and capacitive reactance This method shows the actual impedance vector

Example 87 This example demonstrates the accuracy di erence between GPS and range space DGPS processing In this example, the rover and base receivers are connected to the same antenna; therefore, multipath errors will cancel In addition, the origin of the local tangent plane coordinate system is the antenna location; hence, the correct position estimate is (0, 0, 0)

88 DIFFERENTIAL GPS The measurement matrix H for this 4513 3543 5018 5502 H= 6827 6594 3505 4867 data epoch is calculated to be 8190 10000 6674 10000 3147 10000 8001 10000

Trigonometric Method Using trigonometry, you can determine the RC phase angle more precisely than the pictorial method allows Given the values of X C and R, the RC phase angle is the arctangent of their ratio Phase angle in RC circuits is symbolized by the lowercase Greek letter , just as it is in RL circuits Here are the formulas:

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The pseudoranges corrected for satellite clock bias and the expected range to the origin of the tangent plane reference frame are 331675 326847 r = 333098 334688 where = |pr =0 Using the equation xr = H H

H r ,

= tan 1 (X C /R ) or = arctan (XC /R )

the GPS estimates of tangent plane position and clock bias are 2784 (x xo ) (y yo ) 6986 (z zo ) = 7667 c tr 324177 Note these positioning results are from the era when selective availability was active The L1 pseudorange di erential corrections received at the rover from the base station are 1252 6086 1 = 093 1724 Using the equation xr = H H

When doing problems of this kind, remember to use the capacitive reactance values for X C, and not the capacitance values This means that, if you are given the capacitance, you must use the formula for X C in terms of capacitance and frequency and then calculate the phase angle You should get angles that come out negative or zero This indicates that they re RC phase angles rather than RL phase angles (which are always positive or zero)

H( r + 1 ),

to recalculate the local tangent plane position and clock bias error for the rover receiver yields 037 (x xo ) (y yo ) 041 (z zo ) = 044 c tr 322967

Problem 14-4 Suppose the capacitive reactance in an RC circuit is 3800 and the resistance is 7400 What is the phase angle Find the ratio X C /R = 3800/7400 The calculator display should show you something like 0513513513 Find the arctangent, or tan 1, getting a phase angle of 2718111109 on the calculator display Round this off to 2718 Problem 14-5 Suppose an RC circuit works at a frequency of 350 MHz It has a resistance of 130 and a capacitance of 150 pF What is the phase angle First, find the capacitive reactance for a capacitor of 150 pF at 350 MHz Convert the capacitance to microfarads, getting C = 0000150 F Remember that microfarads go with megahertz (millionths go with millions to cancel each other out) Then:

X C = 1/(628 350 0000150) = 1/0003297 = 303 Now you can find the ratio XC /R = 303/130 = 233 The phase angle is equal to the arctangent of 233, or 668

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